Chris'+Project

Here is the survey for Chris' Survey...please click below and submit the information. Thank you.



So everybody who's already attempted to do this lesson. It wasn't completely up yet... So here is the rest of it.

Go to this link. Watch the video. Pause when it tells you to. Et cetera.

http://www.youtube.com/watch?v=YBpHlSz4q-4



URAQTINVU~It is always so nice to have a confusing subject introduced in a way that one makes sense and two in a way you never thought. I felt I got a prett good understand of the concept I might have to watch the movie again one because it was AMAZING and to just to get another look at it.

KLK: I couldn't open this !

SD: You kinda lost me in the middle but i'll give it a try.... so the new density would be 65/40=1.6 so then you could put it in the formula: 1.6+.5x1.6(1-.5) 1.6+.5x1.6x.5 .8x.5=.4 rate of change?

LJ: Call me confused but if I understand this (which I doubt I do??) new density would be 65/40 = 1.6 P2 = 1.6+.5x1.6(1-.5) = 1.6+.5x1.6x.5 = 1.6+.4 = 2.0 = 80 fish the next year,

TC: Chris, I loved the video. As with KLK and LJ I was stuck at the same problems.

EXAM QUESTIONS!!!

1. Who originated the popular population model?

Verhulst.

The second exam question is located in the powerpoint. For those who can't read it, here it is:

2. What would the next years population be if the current population was 65 fish with a maximum sustainable population of 40? The fixed number is .5.

Use this model:

P2 = Density + Fixed number x Density (1 – Density)

ANSWER:

Density equals 65/40 = 1.6

P2 = 1.6 + .5 x 1.6 (1- 1.6) P2 = 1.6 + .5 x 1.6 x -.6 P2 = 1.6 + -.48

1.12 x 40 = 44.8

The pond was very over populated, so the population dropped dramatically