Mindscapes for Chapter 7.3 & 7.4 please post original response by Friday 11/19(noon) and classmate responses by Sunday 11/21 (noon). If you need to post a drawing or handwritten work and do not have the capability to scan it as a .jpeg it must be submitted to my mailbox (Basement of AB building) by noon on Thursday and I will post in on Friday:
7.3 (1, 2, 5, 6, 13, 21, 22, & 24) 1) [KK] If 52,000,000 people die every year -- about 159,509.20 people die a day. 2) [JL] The chance that the event will not happen that day is 999/1000= .999. For 2 days in a row is .999^= .998. And the event not happening for a year is .999 ^365= .69 CV: This question kind of makes my head hurt. But I get what it's saying. I agree with you. 5) [CV] If we flip a coin 3 times, the chance we'll get 3 heads is 1/8 SD: I got the same thing. URAQTINVU~I did as well 6) [FB]: about 12 students would pick the same number SD:How did you do this one? CV: This makes sense. If there are 50 students, and 4 numbers to choose from. About 12 students should choose each number. KK: exactly, like the book shows too.. 50 students with 4 numbers to choose gives you about 12 students choosing a number ! FB: Yup, I just divided 50/4 and rounded down because I don't like 13 (even though it was .5) and half votes don't exist. 13) [TC] Because if 39 people had died during every 2 week period after 27 weeks that would equal 1053 deaths so one period would have to have at least 40 deaths. 21) [SD]: This problem is talking about a multiple-choice test with 100 questions that has 4 answers and each question is worth one point and no points are taken off if you get it wrong. What is the probability that the person taking the test gets 100%? A: I got (1/4)^100 Then the person is able to eliminate two of the incorrect choices, and then guesses randomly from the other two. What is the probability that they get 100% now? A: I thought that it would be (1/2)^100 LJ: Got the same. 24) [MH] 7.4 (1, 6, 12, 17-20) 1) [JH]red = 1/2, heart = 1/4, queen = 1/13, 1/52 6) [LJ] A lock has a dish with 36 numbers written around its edge. How many different possible combinations are there? 324, What is the probability of randomly guessing the correct one? To be totally honest I have no idea if this is right. The more I look at it the more confused I get. SD: I'm having trouble with this one also. 12) [KK] The chances of winning the lottery .. would be 36 x 36 x 36 x 36 x 36 x 36 -- for the six numbers pulled... giving you a chance of winning around 2 billion.. 17) [JL]In a college town that has 2000 students and you ask 100 random people on the street if they are students or not and 60 people are students. The non-student population would .4 * 2000 = 800 is the non-student population. CV: This all makes sense. It follows the same principals as the question below. 18) [CV] We want to find out how many cars there are in our city. We call a honda dealership and they tell us they have sold 10,000 cars. We sit by a road and count the cars. we count 800 cars total. 250 of them are hondas.
If we estimate how many cars are in the area, we can assume that since about 1/3 of the cars were hondas, there are around 3 times as many cars as honda sold. That totals up to around 30,000 cars. If we did the same experiment with another car dealership, we would get around the same amount of cars total. 19) [FB] The only way i could figure out to do this was to find the probability of getting 2-6 on 4 die rolls and then subtracting 1. 5/6*5/6*5/6*5/6= .482 1-.485=.515 and that is the probability of getting 1 at least once out pf 4 dice rolls 20) [TC] I could not figure this one out.
7.3 (1, 2, 5, 6, 13, 21, 22, & 24)
1) [KK] If 52,000,000 people die every year -- about 159,509.20 people die a day.
2) [JL] The chance that the event will not happen that day is 999/1000= .999. For 2 days in a row is .999^= .998. And the event not happening for a year is .999 ^365= .69
CV: This question kind of makes my head hurt. But I get what it's saying. I agree with you.
5) [CV] If we flip a coin 3 times, the chance we'll get 3 heads is 1/8
SD: I got the same thing.
URAQTINVU~I did as well
6) [FB]: about 12 students would pick the same number
SD:How did you do this one?
CV: This makes sense. If there are 50 students, and 4 numbers to choose from. About 12 students should choose each number.
KK: exactly, like the book shows too.. 50 students with 4 numbers to choose gives you about 12 students choosing a number !
FB: Yup, I just divided 50/4 and rounded down because I don't like 13 (even though it was .5) and half votes don't exist.
13) [TC] Because if 39 people had died during every 2 week period after 27 weeks that would equal 1053 deaths so one period would have to have at least 40 deaths.
21) [SD]: This problem is talking about a multiple-choice test with 100 questions that has 4 answers and each question is worth one point and no points are taken off if you get it wrong.
What is the probability that the person taking the test gets 100%? A: I got (1/4)^100
Then the person is able to eliminate two of the incorrect choices, and then guesses randomly from the other two. What is the probability that they get 100% now? A: I thought that it would be (1/2)^100
LJ: Got the same.
24) [MH]
7.4 (1, 6, 12, 17-20)
1) [JH]red = 1/2, heart = 1/4, queen = 1/13, 1/52
6) [LJ] A lock has a dish with 36 numbers written around its edge. How many different possible combinations are there? 324, What is the probability of randomly guessing the correct one? To be totally honest I have no idea if this is right. The more I look at it the more confused I get.
SD: I'm having trouble with this one also.
12) [KK] The chances of winning the lottery .. would be 36 x 36 x 36 x 36 x 36 x 36 -- for the six numbers pulled... giving you a chance of winning around 2 billion..
17) [JL]In a college town that has 2000 students and you ask 100 random people on the street if they are students or not and 60 people are students. The non-student population would .4 * 2000 = 800 is the non-student population.
CV: This all makes sense. It follows the same principals as the question below.
18) [CV] We want to find out how many cars there are in our city. We call a honda dealership and they tell us they have sold 10,000 cars. We sit by a road and count the cars. we count 800 cars total. 250 of them are hondas.
If we estimate how many cars are in the area, we can assume that since about 1/3 of the cars were hondas, there are around 3 times as many cars as honda sold. That totals up to around 30,000 cars. If we did the same experiment with another car dealership, we would get around the same amount of cars total.
19) [FB] The only way i could figure out to do this was to find the probability of getting 2-6 on 4 die rolls and then subtracting 1. 5/6*5/6*5/6*5/6= .482 1-.485=.515 and that is the probability of getting 1 at least once out pf 4 dice rolls
20) [TC] I could not figure this one out.